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2011 AMC 12A Problem 10

Problem 10 of 25EasierAlgebraGeometryCounting & Probability

A pair of standard 66-sided fair dice is rolled once. The sum of the numbers rolled determines the diameter of a circle. What is the probability that the numerical value of the area of the circle is less than the numerical value of the circle’s circumference?

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Solution

For diameter d,d, area <\lt circumference means πd24<πd,\dfrac{\pi d^2}{4} \lt \pi d, i.e. d<4.d \lt 4. Since d2,d \ge 2, this needs a sum of 22 or 3.3. A sum of 22 has probability 136\dfrac{1}{36} and a sum of 33 has probability 236,\dfrac{2}{36}, totaling 336=112.\dfrac{3}{36} = \dfrac{1}{12}. Thus, the correct answer is B.

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Concepts: dice (probability) · circle · inequality

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.