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2014 AMC 12A Problem 11

Problem 11 of 25IntermediateAlgebra

David drives from his home to the airport to catch a flight. He drives 3535 miles in the first hour, but realizes that he will be 11 hour late if he continues at this speed. He increases his speed by 1515 miles per hour for the rest of the way to the airport and arrives 3030 minutes early. How many miles is the airport from his home?

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Solution

Let dd be the remaining distance after one hour and tt the remaining time until the flight. At 3535 mph he would be an hour late, so d=35(t+1).d=35(t+1). At 5050 mph he is half an hour early, so d=50(t12).d=50\left(t-\tfrac12\right). Setting these equal gives 35t+35=50t25,35t+35=50t-25, so t=4t=4 and d=175.d=175. The total distance is 175+35=210175+35=210 miles. Thus, the correct answer is C.

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Concepts: distance rate and time · system of equations

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.