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2014 AMC 12B Problem 9

Problem 9 of 25EasierGeometry

Convex quadrilateral ABCDABCD has AB=3,AB = 3, BC=4,BC = 4, CD=13,CD = 13, AD=12,AD = 12, and ABC=90,\angle ABC = 90^\circ, as shown. What is the area of the quadrilateral?

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Solution

By the Pythagorean Theorem in right triangle ABC,ABC, AC=32+42=5.AC = \sqrt{3^2+4^2} = 5. Since 52+122=132,5^2 + 12^2 = 13^2, the converse of the Pythagorean Theorem shows DAC=90,\angle DAC = 90^\circ, so DAC\triangle DAC is right. The area of ABC\triangle ABC is 1234=6\tfrac12\cdot3\cdot4 = 6 and the area of DAC\triangle DAC is 12512=30.\tfrac12\cdot5\cdot12 = 30. The quadrilateral has area 6+30=36.6 + 30 = 36. Thus, the correct answer is B.

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Concepts: Pythagorean Theorem · triangle area · area decomposition

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.