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2016 AMC 12A Problem 20

Problem 20 of 25HarderAlgebra

A binary operation ⋄\diamond has the properties that a⋄(b⋄c)=(a⋄b)⋅ca\diamond(b\diamond c)=(a\diamond b)\cdot c and that a⋄a=1a\diamond a=1 for all nonzero real numbers a,a, b,b, and c.c. (Here the dot ⋅\cdot represents the usual multiplication operation.) The solution to the equation 2016⋄(6⋄x)=1002016\diamond(6\diamond x)=100 can be written as pq,\dfrac{p}{q}, where pp and qq are relatively prime positive integers. What is p+q?p+q?

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Solution

Setting b=c=ab=c=a gives a⋄1=a⋄(a⋄a)a\diamond 1=a\diamond(a\diamond a) =(a⋄a)⋅a=a.=(a\diamond a)\cdot a=a. Then setting c=bc=b gives a=a⋄1a=a\diamond 1 =a⋄(b⋄b)=(a⋄b)⋅b,=a\diamond(b\diamond b)=(a\diamond b)\cdot b, so a⋄b=ab.a\diamond b=\dfrac{a}{b}. Therefore 2016⋄(6⋄x)=2016⋄6x=20166x=336x=100, \begin{gathered} 2016\diamond(6\diamond x)\\ =2016\diamond\dfrac{6}{x}\\ =\dfrac{2016}{\frac{6}{x}}\\ =336x=100, \end{gathered} so x=100336=2584x=\dfrac{100}{336}=\dfrac{25}{84} and p+q=25+84=109.p+q=25+84=109. Thus, the correct answer is A.
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