2016 AMC 12A Problem 8

The diagonal of the rectangle from the upper-left corner to the lower-right corner divides the shaded region into four triangles, all meeting at the center of the rectangle. Two of these triangles have a horizontal base of length $1$ and altitude $\frac12\cdot 5=\frac52,$ and the other two have a vertical base of length $1$ and altitude $\frac12\cdot 8=4.$ The total area is $$\begin{gathered} 2\cdot\dfrac12\cdot 1\cdot\dfrac52\\ {}+2\cdot\dfrac12\cdot 1\cdot 4\\ =\dfrac52+4\\ =\dfrac{13}{2}. \end{gathered}$$ Thus, the correct answer is D.