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2018 AMC 12B Problem 10

Problem 10 of 25EasierCombinatoricsProbability & Statistics

A list of 20182018 positive integers has a unique mode, which occurs exactly 1010 times. What is the least number of distinct values that can occur in the list?

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Solution

The mode uses 1010 of the entries, leaving 2008.2008. Because the mode is unique, every other value appears at most 99 times, so at least ⌈20089⌉=224\left\lceil\tfrac{2008}{9}\right\rceil=224 distinct non-mode values are needed. Adding the mode gives 224+1=225.224+1=225. This is achievable: use 99 copies each of 11 through 223,223, ten copies of 224,224, and one copy of 225.225. Thus, the correct answer is D.
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Tagged: mode · pigeonhole principle

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