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2018 AMC 12B Problem 8

Problem 8 of 25EasierGeometry

Line segment AB\overline{AB} is a diameter of a circle with AB=24.AB=24. Point C,C, not equal to AA or B,B, lies on the circle. As point CC moves around the circle, the centroid (center of mass) of ABC\triangle ABC traces out a closed curve missing two points. To the nearest positive integer, what is the area of the region bounded by this curve?

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Solution

Let OO be the center of the circle. The centroid of ABC\triangle ABC is the average of A,A, B,B, and C;C; since OO is the midpoint of AB,\overline{AB}, the centroid lies one-third of the way from OO to C.C. As CC traces the circle of radius 12,12, the centroid traces a circle of radius 1312=4.\tfrac13\cdot12=4. Its area is 16π50.16\pi\approx50. Thus, the correct answer is C.

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Concepts: centroid · homothety · circle area

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.