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2019 AMC 12A Problem 14

Problem 14 of 25IntermediateAlgebra

For a certain complex number c,c, the polynomial P(x)=(x2−2x+2)⋅(x2−cx+4)⋅(x2−4x+8) \begin{aligned} P(x) &= (x^2 - 2x + 2) \\ &\quad {}\cdot (x^2 - cx + 4) \\ &\quad {}\cdot (x^2 - 4x + 8) \end{aligned} has exactly 44 distinct roots. What is ∣c∣?|c|?

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Solution

The factors x2−2x+2x^2 - 2x + 2 and x2−4x+8x^2 - 4x + 8 have roots 1±i1 \pm i and 2±2i,2 \pm 2i, which are 44 distinct values. For PP to have exactly 44 distinct roots, the roots of x2−cx+4x^2 - cx + 4 must lie among these. Their product must equal 4,4, and the only such pair is one root from each factor, for example (1+i)(2−2i)=4.(1 + i)(2 - 2i) = 4. Then c=(1+i)+(2−2i)=3−i,c = (1 + i) + (2 - 2i) = 3 - i, so ∣c∣=32+12=10.|c| = \sqrt{3^2 + 1^2} = \sqrt{10}. Thus, the correct answer is E.
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Tagged: complex number · polynomial · Vieta’s Formulas

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