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2019 AMC 12A Problem 17

Problem 17 of 25IntermediateAlgebra

Let sks_k denote the sum of the kkth powers of the roots of the polynomial x3−5x2+8x−13.x^3 - 5x^2 + 8x - 13. In particular, s0=3,s_0 = 3, s1=5,s_1 = 5, and s2=9.s_2 = 9. Let a,a, b,b, and cc be real numbers such that sk+1=a sk+b sk−1+c sk−2s_{k+1} = a\,s_k + b\,s_{k-1} + c\,s_{k-2} for k=2,k = 2, 3,3, ….\ldots. What is a+b+c?a + b + c?

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Solution

Every root rr satisfies r3=5r2−8r+13,r^3 = 5r^2 - 8r + 13, so rk+1=5rk−8rk−1+13rk−2.r^{k+1} = 5r^k - 8r^{k-1} + 13r^{k-2}. Summing over the three roots gives sk+1=5sk−8sk−1+13sk−2,s_{k+1} = 5s_k - 8s_{k-1} + 13s_{k-2}, so a=5,a = 5, b=−8,b = -8, c=13.c = 13. Therefore a+b+c=5−8+13=10.a + b + c = 5 - 8 + 13 = 10. Thus, the correct answer is D.
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Tagged: Newton’s Sums · polynomial · recursion

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