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2019 AMC 12B Problem 17

Problem 17 of 25IntermediateAlgebraGeometry

How many nonzero complex numbers zz have the property that 0,0, z,z, and z3,z^3, when represented by points in the complex plane, are the three distinct vertices of an equilateral triangle?

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Solution

The three points form an equilateral triangle iff ∣z∣=∣z3∣=∣z3−z∣.|z|=|z^3|=|z^3-z|. From ∣z∣=∣z3∣=∣z∣3|z|=|z^3|=|z|^3 we get ∣z∣=1.|z|=1. Then ∣z3−z∣=∣z∣ ∣z2−1∣=∣z2−1∣,|z^3-z|=|z|\,|z^2-1|=|z^2-1|, so we need ∣z2−1∣=1.|z^2-1|=1. Writing z=eiθ,z=e^{i\theta}, ∣z2−1∣=2∣sin⁡θ∣=1,|z^2-1|=2|\sin\theta|=1, so ∣sin⁡θ∣=12.|\sin\theta|=\dfrac12. This gives θ=30∘,150∘,210∘,330∘,\theta=30^\circ,150^\circ,210^\circ,330^\circ, four values of z,z, all yielding distinct vertices. Thus, D is the correct answer.
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Tagged: complex number · equilateral triangle

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