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2019 AMC 12B Problem 7

Problem 7 of 25EasierAlgebra

What is the sum of all real numbers xx for which the median of the numbers 4,4, 6,6, 8,8, 17,17, and xx is equal to the mean of those five numbers?

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Solution

The mean is 4+6+8+17+x5=35+x5.\dfrac{4+6+8+17+x}{5}=\dfrac{35+x}{5}. If x6,x\le6, the median is 6,6, so 35+x5=6\dfrac{35+x}{5}=6 gives x=5,x=-5, which is consistent. If 6<x<8,6\lt x\lt8, the median is x,x, so 35+x5=x\dfrac{35+x}{5}=x gives x=8.75,x=8.75, not in range. If x8,x\ge8, the median is 8,8, so 35+x5=8\dfrac{35+x}{5}=8 gives x=5,x=5, not in range. The only solution is x=5,x=-5, so the sum is 5.-5. Thus, A is the correct answer.

More practice

Concepts: mean · median (data) · casework

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.