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2021 AMC 12A Problem 6

Problem 6 of 25EasierAlgebraCounting & Probability

A deck of cards has only red cards and black cards. The probability of a randomly chosen card being red is 13.\dfrac13. When 44 black cards are added to the deck, the probability of choosing red becomes 14.\dfrac14. How many cards were in the deck originally?

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Solution

Let rr be the number of red cards and tt the total. From rt=13\dfrac{r}{t} = \dfrac13 we get t=3r.t = 3r. After adding 44 black cards, rt+4=14,\dfrac{r}{t+4} = \dfrac14, so t+4=4r.t + 4 = 4r. Substituting t=3rt = 3r gives 3r+4=4r,3r + 4 = 4r, so r=4r = 4 and t=12.t = 12. Thus, the correct answer is C.

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Concepts: basic probability · system of equations

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.