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2023 AMC 12A Problem 12

Problem 12 of 25IntermediateAlgebra

What is the value of 2313+4333+6353++183173? \begin{gathered} 2^3-1^3+4^3-3^3+6^3-5^3\\ {}+\cdots+18^3-17^3? \end{gathered}

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Solution

Group into pairs (2k)3(2k1)3(2k)^3-(2k-1)^3 for k=1,,9.k=1,\ldots,9. Expanding, (2k)3(2k1)3=12k26k+1. \begin{gathered} (2k)^3-(2k-1)^3\\ {}=12k^2-6k+1. \end{gathered} Summing for k=1k=1 to 9,9, with k2=285\sum k^2=285 and k=45,\sum k=45, gives 12285645+9=3420270+9=3159. \begin{gathered} 12\cdot 285-6\cdot 45+9\\ {}=3420-270+9\\ {}=3159. \end{gathered} Thus, the correct answer is D.

More practice

Concepts: sum and difference of cubes · sum of first n squares

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.