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2023 AMC 12A Problem 6

Problem 6 of 25EasierAlgebraGeometry

Points AA and BB lie on the graph of y=log⁡2x.y=\log_2 x. The midpoint of AB‾\overline{AB} is (6,2).(6,2). What is the positive difference between the xx-coordinates of AA and B?B?

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Solution

Let the xx-coordinates be x1x_1 and x2.x_2. The midpoint gives x1+x2=12,x_1+x_2=12, and the average of the yy-values gives log⁡2x1+log⁡2x2=4,\log_2 x_1+\log_2 x_2=4, so x1x2=24=16.x_1x_2=2^4=16. Then ∣x1−x2∣=(x1+x2)2−4x1x2=144−64=80=45. \begin{gathered} |x_1-x_2|\\ {}=\sqrt{(x_1+x_2)^2-4x_1x_2}\\ {}=\sqrt{144-64}\\ {}=\sqrt{80}\\ {}=4\sqrt5. \end{gathered} Thus, the correct answer is D.
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Tagged: logarithm · midpoint · algebraic manipulation

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