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2023 AMC 12B Problem 10

Problem 10 of 25EasierGeometry

In the xyxy-plane, a circle of radius 44 with center on the positive xx-axis is tangent to the yy-axis at the origin, and a circle with radius 1010 with center on the positive yy-axis is tangent to the xx-axis at the origin. What is the slope of the line passing through the two points at which these circles intersect?

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Solution

The circles are (x4)2+y2=16(x-4)^2+y^2=16 and x2+(y10)2=100,x^2+(y-10)^2=100, i.e. x2+y2=8xx^2+y^2=8x and x2+y2=20y.x^2+y^2=20y. Subtracting gives 8x=20y,8x=20y, so the intersection points lie on y=25x,y=\tfrac{2}{5}x, which has slope 25.\tfrac{2}{5}. Thus, the correct answer is E.

More practice

Concepts: circle · radical axis · slope

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.