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2023 AMC 12B Problem 8

Problem 8 of 25EasierCounting & Probability

How many nonempty subsets BB of {0,1,2,3,,12}\{0,1,2,3,\ldots,12\} have the property that the number of elements in BB is equal to the least element of B?B? For example, B={4,6,8,11}B=\{4,6,8,11\} satisfies the condition.

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Solution

If the least element is m (m1),m\ (m\ge 1), then B=m|B|=m and the remaining m1m-1 elements come from {m+1,,12},\{m+1,\ldots,12\}, a set of size 12m.12-m. The count is m1(12mm1)=(110)+(101)+(92)+(83)+(74)+(65), \begin{aligned} \sum_{m\ge 1}\binom{12-m}{m-1} &=\binom{11}{0} \\ &\quad {}+\binom{10}{1} \\ &\quad {}+\binom{9}{2} \\ &\quad {}+\binom{8}{3} \\ &\quad {}+\binom{7}{4} \\ &\quad {}+\binom{6}{5}, \end{aligned} which equals 1+10+36+56+35+61+10+36+56+35+6 =144.=144. Thus, the correct answer is D.

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Concepts: combinations · casework

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.