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2023 AMC 12B Problem 14

Problem 14 of 25IntermediateAlgebraNumber TheoryCounting & Probability

For how many ordered pairs (a,b)(a,b) of integers does the polynomial x3+ax2+bx+6x^3+ax^2+bx+6 have 33 distinct integer roots?

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Solution

By Vieta, the three distinct integer roots multiply to 6.-6. The sets of three distinct integers with product 6-6 are {1,2,3},\{1,2,-3\}, {1,2,3},\{1,-2,3\}, {1,2,3},\{-1,2,3\}, {1,2,3},\{-1,-2,-3\}, and {1,1,6}.\{1,-1,6\}. Each set determines a=(p+q+r)a=-(p+q+r) and b=pq+qr+rp,b=pq+qr+rp, and all five give different pairs, so there are 55 ordered pairs (a,b).(a,b). Thus, the correct answer is A.

More practice

Concepts: Vieta’s Formulas · factor · systematic listing

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.