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2025 AMC 12A Problem 7

Problem 7 of 25EasierAlgebra

In a certain alien world, the maximum running speed vv of an organism is dependent on its number of toes nn and number of eyes m.m. The relationship can be expressed as v=knambv = k n^a m^b centimeters per hour, where k,k, a,a, and bb are integer constants. In a population where all organisms have 55 toes, logv=4+2logm;\log v = 4 + 2\log m; and in a population where all organisms have 2525 eyes, logv=4+4logn,\log v = 4 + 4\log n, where the logarithms are base 10.10. What is k+a+b?k + a + b?

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Solution

Taking logarithms, logv=logk+alogn+blogm.\log v = \log k + a\log n + b\log m. With n=5,n = 5, this reads logv=(logk+alog5)\log v = (\log k + a\log 5) +blogm,+ b\log m, matching 4+2logm,4 + 2\log m, so b=2b = 2 and logk+alog5=4.\log k + a\log 5 = 4. With m=25,m = 25, it reads logv=(logk+blog25)\log v = (\log k + b\log 25) +alogn,+ a\log n, matching 4+4logn,4 + 4\log n, so a=4a = 4 and logk+2log25=4.\log k + 2\log 25 = 4. Then logk=4log625\log k = 4 - \log 625 =log10000625= \log\dfrac{10000}{625} =log16,= \log 16, so k=16.k = 16. Hence k+a+b=16+4+2=22.k + a + b = 16 + 4 + 2 = 22. Thus, the correct answer is C.

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Concepts: logarithm · system of equations

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.