2014/15 AHSMC Part 1 Problem 6Problem 6 of 16The sum of four consecutive integers is nnn. The largest of these four numbers isAnswer choicesAnnn1Bn4\dfrac{n}{4}4n2Cn−22\dfrac{n-2}{2}2n−23Dn+64\dfrac{n+6}{4}4n+64Enone of these5Submit answerShow solutionSolutionLet n=(k−3)+(k−2)+(k−1)+k=4k−6n = (k-3) + (k-2) + (k-1) + k = 4k - 6n=(k−3)+(k−2)+(k−1)+k=4k−6. Then k=n+64k = \dfrac{n+6}{4}k=4n+6. The answer is (D).University of AlbertaCopy problem