2014/15 AHSMC Part 1 Problem 9
Problem 9 of 16
The number of integer pairs such that is
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Solution
Clearly , so that . Since is an integer, we can only have or , with and respectively. The answer is (C).
Problem 9 of 16
The number of integer pairs such that is
Clearly , so that . Since is an integer, we can only have or , with and respectively. The answer is (C).