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2000 AMC 10 Problem 1

Problem 1 of 25EasierAlgebraNumber Theory

In the year 2001,2001, the United States will host the International Mathematical Olympiad. Let I,I, M,M, and OO be distinct positive integers such that the product IMO=2001.I \cdot M \cdot O = 2001. What is the largest possible value of the sum I+M+O?I + M + O?

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Solution

Factoring gives 2001=32329.2001 = 3 \cdot 23 \cdot 29. If one factor is 1,1, the possible pairs for the other two factors are (3,667),(3,667), (23,87),(23,87), and (29,69).(29,69). Their corresponding sums with 11 are 671,671, 111,111, and 99.99. (The pair (1,2001)(1,2001) would repeat the factor 1.1.) If no factor is 1,1, all three prime factors must be split among the three integers, giving only 3,23,293,23,29 and a much smaller sum. Therefore, the largest possible sum is 1+3+667=671.1 + 3 + 667 = 671. Thus, the correct answer is E.

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Concepts: prime factorization · optimization

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.