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2000 AMC 10 Problem 14

Problem 14 of 25IntermediateAlgebraNumber Theory

Mrs. Walter gave an exam in a mathematics class of five students. She entered the scores in random order into a spreadsheet, which recalculated the class average after each score was entered. Mrs. Walter noticed that after each score was entered, the average was always an integer. The scores (listed in ascending order) were 71,71, 76,76, 80,80, 82,82, and 91.91. What was the last score Mrs. Walter entered?

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Solution

The residues of 71,76,80,82,9171, 76, 80, 82, 91 modulo 33 are 2,1,2,1,1.2, 1, 2, 1, 1. The sum of the first three scores must be divisible by 3,3, and the only such triple is 76+82+91=249,76 + 82 + 91 = 249, so the third score entered is 9191 and the first two are 7676 and 82.82. Since 249249 is one more than a multiple of 4,4, the fourth score must be three more than a multiple of 4,4, which only 7171 satisfies. That leaves 8080 as the fifth and last score. Indeed 76,158,249,320,40076, 158, 249, 320, 400 are divisible by 1,2,3,4,5.1, 2, 3, 4, 5. Thus, the correct answer is C.

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Concepts: divisibility · modular arithmetic · mean

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.