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2000 AMC 10 Problem 10

Problem 10 of 25EasierGeometryProblem-Solving Techniques

The sides of a triangle with positive area have lengths 4,4, 6,6, and x.x. The sides of a second triangle with positive area have lengths 4,4, 6,6, and y.y. What is the smallest positive number that is not a possible value of ∣x−y∣?|x - y|?

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Solution

By the triangle inequality, each of xx and yy can be any number strictly between 6−4=26 - 4 = 2 and 6+4=10.6 + 4 = 10. Then ∣x−y∣|x - y| can take any value with 0≤∣x−y∣<8.0 \le |x - y| \lt 8. The smallest positive number not attainable is 10−2=8.10 - 2 = 8. Thus, the correct answer is D.
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Tagged: triangle inequality · bounding to limit cases

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