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2004 AMC 10A Problem 23

Problem 23 of 25HarderGeometry

Circles A,A, B,B, and CC are externally tangent to each other and internally tangent to circle D.D. Circles BB and CC are congruent. Circle AA has radius 11 and passes through the center of D.D. What is the radius of circle B?B?

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Solution

Because circle AA passes through DD’s center and is internally tangent to D,D, circle DD has radius 2.2. Place DD’s center at the origin and AA’s center at (1,0).(-1, 0). Let circle BB have radius rr and center (x,r),(x, r), using the symmetry of BB and CC about the horizontal axis. Tangency gives (x+1)2+r2=(1+r)2,x2+r2=(2r)2. \begin{aligned} (x + 1)^2 + r^2 &= (1 + r)^2, \\ x^2 + r^2 &= (2 - r)^2. \end{aligned} Subtracting yields x=3r2.x = 3r - 2. Substituting into the second equation gives 9r28r=0,9r^2 - 8r = 0, so r=89.r = \dfrac{8}{9}. Thus, the correct answer is D.

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Concepts: tangent circles · coordinate geometry · Pythagorean Theorem

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