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2004 AMC 10A Problem 24

Problem 24 of 25HarderAlgebra

Let a1,a_1, a2,a_2, \ldots be a sequence with the following properties: a1=1,a_1 = 1, and a2n=nana_{2n} = n \cdot a_n for any positive integer n.n. What is the value of a2100?a_{2^{100}}?

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Solution

Applying the rule repeatedly, a21=20,a22=21,a23=21+2,a24=21+2+3, \begin{aligned} a_{2^1} &= 2^0, \\ a_{2^2} &= 2^1, \\ a_{2^3} &= 2^{1+2}, \\ a_{2^4} &= 2^{1+2+3}, \ldots \end{aligned} so in general a2n=21+2++(n1)=2n(n1)2.a_{2^n} = 2^{1 + 2 + \cdots + (n - 1)} = 2^{\frac{n(n-1)}{2}}. For n=100,n = 100, the exponent is 100992=4950,\dfrac{100 \cdot 99}{2} = 4950, so a2100=24950.a_{2^{100}} = 2^{4950}. Thus, the correct answer is D.

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