Skip to main content

2004 AMC 10B Problem 10

Problem 10 of 25EasierAlgebra

A grocer makes a display of cans in which the top row has one can and each lower row has two more cans than the row above it. If the display contains 100100 cans, how many rows does it contain?

Answer choices

Show solution

Solution

The rows hold 1,3,5,…1, 3, 5, \ldots cans, and the sum of the first nn odd numbers is n2.n^2. Setting n2=100n^2 = 100 gives n=10.n = 10. Thus, the correct answer is D.
AoPS wiki

Tagged: sum of first n odd numbers

More practice