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2004 AMC 10B Problem 17

Problem 17 of 25IntermediateAlgebraNumber Theory

The two digits in Jack’s age are the same as the digits in Bill’s age, but in reverse order. In five years Jack will be twice as old as Bill will be then. What is the difference in their current ages?

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Solution

Let Jack’s age be 10x+y10x + y and Bill’s be 10y+x.10y + x. In five years 10x+y+5=2(10y+x+5),10x + y + 5 = 2(10y + x + 5), which simplifies to 8x=19y+5.8x = 19y + 5. Since xx and yy are digits, the only solution is y=1,y = 1, x=3.x = 3. So Jack is 3131 and Bill is 13,13, a difference of 18.18. Thus, the correct answer is B.

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Concepts: ages · digits · Diophantine Equation

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.