Skip to main content

2007 AMC 10B Problem 13

Problem 13 of 25IntermediateGeometry

Two circles of radius 22 are centered at (2,0)(2,0) and at (0,2).(0,2). What is the area of the intersection of the interiors of the two circles?

Answer choices

Show solution

Solution

The two circles intersect at (0,0)(0,0) and (2,2).(2,2). By symmetry, half the intersection is formed by removing an isosceles right triangle of leg length 22 from a quarter of one circle. The quarter-circle has area 14π(2)2=π\dfrac14\pi(2)^2=\pi and the triangle has area 12(2)2=2.\dfrac12(2)^2=2. Therefore the whole region has area 2(π2).2(\pi-2). Thus, the correct answer is D.

More practice

Concepts: sector · area decomposition · symmetry

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.