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2007 AMC 10B Problem 8

Problem 8 of 25EasierNumber TheoryCounting & Probability

On the trip home from the meeting where this AMC 1010 was constructed, the Contest Chair noted that his airport parking receipt had digits of the form bbcac,bbcac, where 0a<b<c9,0\le a\lt b\lt c\le 9, and bb was the average of aa and c.c. How many different five-digit numbers satisfy all these properties?

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Solution

Once aa and cc are chosen, b=a+c2b=\dfrac{a+c}{2} is determined, and a<b<ca\lt b\lt c holds automatically. For bb to be an integer, aa and cc must share parity. Choosing two even digits from {0,2,4,6,8}\{0,2,4,6,8\} gives (52)=10\binom{5}{2}=10 pairs, and choosing two odd digits from {1,3,5,7,9}\{1,3,5,7,9\} gives another 10.10. This yields 2020 valid numbers. Thus, the correct answer is D.

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Concepts: digits · parity · combinations

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.