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2007 AMC 10B Problem 6

Problem 6 of 25EasierAlgebra

The 20072007 AMC 1010 will be scored by awarding 66 points for each correct response, 00 points for each incorrect response, and 1.51.5 points for each problem left unanswered. After looking over the 2525 problems, Sarah has decided to attempt the first 2222 and leave only the last 33 unanswered. How many of the first 2222 problems must she solve correctly in order to score at least 100100 points?

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Solution

The three blank problems give 31.5=4.53\cdot 1.5 = 4.5 points, so Sarah needs 1004.5=95.5100-4.5=95.5 points from the first 22.22. Since 95.56\frac{95.5}{6} lies between 1515 and 16,16, she must answer at least 1616 correctly, which would give a score of 100.5.100.5. Thus, the correct answer is D.

More practice

Concepts: inequality · linear equation

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.