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2009 AMC 10B Problem 17

Problem 17 of 25IntermediateGeometry

Five unit squares are arranged in the coordinate plane as shown, with the lower left corner at the origin. The slanted line, extending from (a,0)(a,0) to (3,3),(3,3), divides the entire region into two regions of equal area. What is a?a?

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Solution

The five unit squares have total area 5,5, so each region must have area 52.\dfrac52. The region to the lower right of the line is a right triangle with legs 3a3-a and 3,3, minus the one unit square it does not cover. Setting its area to 52\dfrac52 gives 3(3a)21=52, \dfrac{3(3-a)}{2}-1=\dfrac52, so 3(3a)=73(3-a)=7 and a=23.a=\dfrac23. Thus, the correct answer is C.

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Concepts: triangle area · area decomposition · coordinate geometry

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.