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2009 AMC 10B Problem 23

Problem 23 of 25HarderAlgebraCounting & Probability

Rachel and Robert run on a circular track. Rachel runs counterclockwise and completes a lap every 9090 seconds, and Robert runs clockwise and completes a lap every 8080 seconds. Both start from the start line at the same time. At some random time between 1010 minutes and 1111 minutes after they begin to run, a photographer standing inside the track takes a picture that shows one-fourth of the track, centered on the starting line. What is the probability that both Rachel and Robert are in the picture?

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Solution

The picture spans 18\dfrac18 lap on each side of the start. After 600600 seconds Rachel is 3030 seconds short of the line; running 14\dfrac14 lap in 22.522.5 seconds, she is in view between 3011.25=18.7530-11.25=18.75 and 30+11.25=41.2530+11.25=41.25 seconds of the 1010th minute. After 600600 seconds Robert is 4040 seconds from the line; running 14\dfrac14 lap in 2020 seconds, he is in view between 3030 and 5050 seconds. Both appear between 3030 and 41.2541.25 seconds, a window of length 11.2511.25 out of 60,60, so the probability is 11.2560=316.\dfrac{11.25}{60}=\dfrac{3}{16}. Thus, the correct answer is C.

More practice

Concepts: geometric probability · distance rate and time

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.