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2010 AMC 10A Problem 1

Problem 1 of 25EasierAlgebra

Mary’s top book shelf holds five books with the following widths, in centimeters: 6,6, 12,\dfrac{1}{2}, 1,1, 2.5,2.5, and 10.10. What is the average book width, in centimeters?

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Solution

Adding the five widths gives 6+12+1+2.5+10=20.6+\dfrac12+1+2.5+10=20. The average is 20÷5=4.20\div5=4. Thus, D is the correct answer.

More practice

Concepts: mean · decimal

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.