2010 AMC 10A Problem 10

Note that on a normal year, we have that $$365 = 52 \cdot 7 + 1,$$ which means that for a specific day, it moves to the day after the next year. On a leap year, the day of the week moves forward two since there is an extra day. Then in $2009,$ this day falls on a Wednesday. In $2010,$ it falls on a Thursday. Similarly, in $2011,$ it falls on a Friday. In $2012,$ however, since it is a leap year, it falls on a Sunday. Now, for the next three years, the day moves forward one. Then in $2016,$ it moves forward two, landing on a Friday. Finally, in $2017,$ the day of the week is a Saturday. Thus, E is the correct answer.