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2010 AMC 10A Problem 6

Problem 6 of 25EasierAlgebra

For positive numbers xx and yy the operation (x,y)\spadesuit (x,y) is defined as (x,y)=x1y\spadesuit (x,y) = x-\dfrac{1}{y} What is (2,(2,2))?\spadesuit (2,\spadesuit (2,2))?

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Solution

Evaluating the inner expression, we get (2,2)=212=32. \spadesuit (2, 2) = 2 - \dfrac{1}{2} = \dfrac{3}{2}. Then we have (2,32)=2132=43. \spadesuit \left(2, \dfrac{3}{2}\right) = 2 - \dfrac{1}{\frac{3}{2}} = \dfrac{4}{3}. Thus, C is the correct answer.

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Concepts: custom operation · fraction

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