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2016 AMC 10A Problem 2

Problem 2 of 25EasierAlgebra

For what value of xx does 10x1002x=10005?10^{x} \cdot 100^{2x}=1000^{5}?

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Solution

Rewrite all bases as powers of 1010: 10x1002x=10x(102)2x=105x,\small 10^x\cdot100^{2x}=10^x\cdot(10^2)^{2x}=10^{5x}, and 10005=(103)5=1015.1000^5=(10^3)^5=10^{15}. Therefore 5x=155x=15, so x=3x=3. Thus, the correct answer is C.

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Concepts: exponent

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.