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2001 AMC 12 Problem 18

Problem 18 of 25IntermediateGeometry

A circle centered at AA with a radius of 11 and a circle centered at BB with a radius of 44 are externally tangent. A third circle is tangent to the first two and to one of their common external tangents as shown. The radius of the third circle is

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Solution

When two mutually tangent circles of radii rr and ss both rest on a line, the distance between their points of tangency is 2rs.2\sqrt{rs}. The big circles’ contact points are 214=42\sqrt{1 \cdot 4} = 4 apart. Placing the small circle of radius xx between them, its two tangent distances add up: 21x+24x=4. 2\sqrt{1 \cdot x} + 2\sqrt{4 \cdot x} = 4. Then 6x=4,6\sqrt{x} = 4, so x=23\sqrt{x} = \dfrac{2}{3} and x=49.x = \dfrac{4}{9}. Thus, the correct answer is D.

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Concepts: tangent circles · Pythagorean Theorem

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.