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2001 AMC 12 Problem 19

Problem 19 of 25HarderAlgebra

The polynomial P(x)=x3+ax2+bx+cP(x) = x^3 + ax^2 + bx + c has the property that the mean of its zeros, the product of its zeros, and the sum of its coefficients are all equal. If the yy-intercept of the graph of y=P(x)y = P(x) is 2,2, what is b?b?

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Solution

The yy-intercept is P(0)=c=2.P(0) = c = 2. By Vieta’s formulas the product of the zeros is c=2,-c = -2, the mean of the zeros is a3,-\dfrac{a}{3}, and the sum of the coefficients is P(1)=1+a+b+c.P(1) = 1 + a + b + c. All three are equal to 2.-2. From a3=2-\dfrac{a}{3} = -2 we get a=6.a = 6. Then 1+a+b+c=21 + a + b + c = -2 becomes 1+6+b+2=2,1 + 6 + b + 2 = -2, so b=11.b = -11. Thus, the correct answer is A.

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Concepts: Vieta’s Formulas · polynomial

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