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2004 AMC 12B Problem 15

Problem 15 of 25IntermediateAlgebraNumber Theory

The two digits in Jack’s age are the same as the digits in Bill’s age, but in reverse order. In five years Jack will be twice as old as Bill will be then. What is the difference in their current ages?

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Solution

Let Jack be 10x+y10x + y and Bill be 10y+x.10y + x. Then 10x+y+5=2(10y+x+5),10x + y + 5 = 2(10y + x + 5), so 8x=19y+5.8x = 19y + 5. Testing digits, only y=1,x=3y = 1, x = 3 works, so Jack is 3131 and Bill is 13.13. The difference is 3113=18.31 - 13 = 18. Thus, the correct answer is B.

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Concepts: ages · place value · linear equation

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.