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2004 AMC 12B Problem 18

Problem 18 of 25IntermediateGeometry

Points AA and BB are on the parabola y=4x2+7x1,y = 4x^2 + 7x - 1, and the origin is the midpoint of AB.\overline{AB}. What is the length of AB?AB?

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Solution

Let B=(a,b)B = (a, b) and A=(a,b).A = (-a, -b). Then 4a2+7a1=b4a^2 + 7a - 1 = b and 4a27a1=b.4a^2 - 7a - 1 = -b. Subtracting gives 14a=2b,14a = 2b, so b=7a.b = 7a. Then 4a2+7a1=7a4a^2 + 7a - 1 = 7a gives a2=14,a^2 = \dfrac14, and b2=49a2=494.b^2 = 49a^2 = \dfrac{49}{4}. So AB=2a2+b2AB = 2\sqrt{a^2 + b^2} =2504=52.= 2\sqrt{\dfrac{50}{4}} = 5\sqrt{2}. Thus, the correct answer is E.

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Concepts: parabola · midpoint · distance formula

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