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2010 AMC 12A Problem 1

Problem 1 of 25EasierArithmetic

What is (20−(2010−201))(20-(2010-201)) +(2010−(201−20))?+(2010-(201-20))?

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Solution

Distributing the negative signs gives (20−2010+201)+(2010−201+20)=40. \begin{aligned} &(20-2010+201) \\ &\quad {}+(2010-201+20)=40. \end{aligned} Thus, C is the correct answer.
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