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2015 AMC 12A Problem 1

Problem 1 of 25EasierAlgebra

What is the value of (20−1+52+0)−1×5?(2^0-1+5^2+0)^{-1}\times 5?

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Solution

Inside the parentheses, 20−1+52+0=1−1+25+0=25. \begin{aligned} &2^0-1+5^2+0 \\ &\quad = 1-1+25+0 = 25. \end{aligned} Then (25)−1×5=525=15.(25)^{-1}\times 5 = \dfrac{5}{25} = \dfrac{1}{5}. Thus, the correct answer is C.

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Concepts: order of operations · exponent

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