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2015 AMC 12A Problem 9

Problem 9 of 25EasierCounting & Probability

A box contains 22 red marbles, 22 green marbles, and 22 yellow marbles. Carol takes 22 marbles from the box at random; then Claudia takes 22 of the remaining marbles at random; and then Cheryl takes the last 22 marbles. What is the probability that Cheryl gets 22 marbles of the same color?

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Solution

Because the marbles left for Cheryl are determined at random, her two marbles are equally likely to be any pair. Fixing her first marble, the second is equally likely to be any of the 55 remaining marbles. Exactly one of those 55 matches the first marble in color, so the probability is 15.\dfrac{1}{5}. Thus, the correct answer is C.

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Concepts: basic probability · symmetry

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.