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2025 AMC 12B Problem 13

Problem 13 of 25IntermediateCounting & Probability

A circle has been divided into 66 sectors of different sizes. Then 22 of the sectors are painted red, 22 painted green, and 22 painted blue so that no two neighboring sectors are painted the same color. One such coloring is shown below. How many different colorings are possible?

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Solution

The two sectors of each color must be a non-adjacent pair, so a coloring is a way to split the 66 cyclic sectors into three non-adjacent pairs together with an assignment of the three colors. The non-adjacent pairs are the edges of the complement of the 66-cycle, the triangular prism, which has 44 perfect matchings. Assigning the three colors in 3!3! ways gives 4×6=244 \times 6 = 24 colorings. Thus, the correct answer is D.

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Concepts: graph theory · multiplication principle

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.