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2025 AMC 12B Problem 5

Problem 5 of 25EasierNumber Theory

Positive integers xx and yy satisfy the equation 57x+22y=400.57x + 22y = 400. What is the least possible value of x+y?x + y?

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Solution

Modulo 22,22, the equation gives 13x4,13x \equiv 4, so x2(mod22).x \equiv 2 \pmod{22}. With 57x<400,57x \lt 400, the only option is x=2,x = 2, which gives 22y=286,22y = 286, so y=13.y = 13. Then x+y=15.x + y = 15. Thus, the correct answer is E.

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Concepts: Diophantine Equation · modular arithmetic

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.