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2025 AMC 12B Problem 3

Problem 3 of 25EasierAlgebra

What is the value of i(i1)(i2)(i3),i(i-1)(i-2)(i-3), where i=1?i = \sqrt{-1}?

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Solution

i(i1)=i2i=1i,i(i-1) = i^2 - i = -1 - i, and (i2)(i3)=i25i+6(i-2)(i-3) = i^2 - 5i + 6 =55i.= 5 - 5i. Then (1i)(55i)=5+5i5i+5i2=55=10. \begin{gathered} (-1-i)(5-5i) = -5 \\ {}+ 5i - 5i \\ {}+ 5i^2 \\ = -5 - 5 = -10. \end{gathered} Thus, the correct answer is D.

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Concepts: complex number

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.