2012/13 AHSMC Part 1 Problem 2

Problem 2 of 16

Meeny, Miny and Moe were playing tennis. From the second game on, the one who sat out the preceding game would replace the loser of that game. At the end, Meeny played $17$ games and Miny played $35$ games. How many games did Moe play?

Show solution

Solution

Since Meeny played $17$ games, Miny and Moe played each other at most $17 + 1 = 18$ times, and each could play at most $18 + 17 = 35$ games. As Miny played $35$ games, Moe did not play Meeny but played Miny $18$ times. The answer is (A).

University of Alberta

Answer choices

Solution