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2021 AMC 10A Problem 1

Problem 1 of 25EasierAlgebra

What is the value of (22−2)−(32−3)+(42−4)?(2^2-2)-(3^2-3)+(4^2-4)?

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Solution

(22−2)−(32−3)+(42−4)=2−6+12=8. \begin{aligned} (2^2 - 2) - &(3^2 - 3) + (4^2 - 4) \\ &= 2 - 6 + 12 \\ &= 8. \end{aligned} Thus, D is the correct answer.

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Concepts: order of operations

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.