2021 AMC 10A Problem 1Problem 1 of 25·Easier·ArithmeticWhat is the value of (22−2)−(32−3)+(42−4)?(2^2-2)-(3^2-3)+(4^2-4)?(22−2)−(32−3)+(42−4)?Answer choicesA1111B2222C5553D8884E1212125Submit answerStuck? Show hintsShow solutionSolution(22−2)−(32−3)+(42−4)=2−6+12=8. \begin{aligned} (2^2 - 2) - &(3^2 - 3) + (4^2 - 4) \\ &= 2 - 6 + 12 \\ &= 8. \end{aligned} (22−2)−(32−3)+(42−4)=2−6+12=8. Thus, D is the correct answer.AoPS wikiCopy problemTagged: order of operations