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2021 AMC 10A Problem 4

Problem 4 of 25EasierAlgebra

A cart rolls down a hill, traveling 55 inches the first second and accelerating so that during each successive 11-second time interval, it travels 77 inches more than during the previous 11-second interval. The cart takes 3030 seconds to reach the bottom of the hill. How far, in inches, does it travel?

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Solution

The distance travelled every second forms an arithmetic sequence: 5,5+7,5+27, 5, 5 + 7, 5 + 2 \cdot 7, \ldots The standard arithmetic-sequence sum formula is na1+an2. n\cdot\dfrac{a_1+a_n}{2}. We know the number of terms is 3030 and the first term is 5.5. The last term is 5+297=208.5 + 29 \cdot 7 = 208. Plugging these values into the expression yields 305+2082=15213=3195. 30 \cdot \dfrac{5 + 208}{2} = 15 \cdot 213 = 3195. Thus, D is the correct answer.

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Concepts: arithmetic sequence · summation

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.