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2022 AMC 10B Problem 1

Problem 1 of 25EasierAlgebra

Define x  yx~\diamondsuit~ y to be xy|x-y| for all real numbers xx and y.y. What is the value of (1  (2  3))((1  2)  3)?(1~\diamondsuit~(2~\diamondsuit~3))-((1~\diamondsuit~2)~\diamondsuit~3)?

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Solution

Working from the innermost operations outward gives 1(23)=123=0,(12)3=123=2. \begin{aligned} 1\mathbin\diamondsuit(2\mathbin\diamondsuit3)&=|1-|2-3||=0,\\ (1\mathbin\diamondsuit2)\mathbin\diamondsuit3&=||1-2|-3|=2. \end{aligned} Therefore, the given difference is 02=2.0-2=-2. Thus, the answer is A .

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Concepts: custom operation · absolute value

Problem text and solution from the LIVE past-contest archive. See also the AoPS wiki page for community solutions.